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Corrections to the material #16
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Hi Misha, Question 1: I know that the branch cut of a complex squareroot goes to the left (from bp to -inf.). I just thought the most common choice in particle physics would be to the right. But technically you could rotate it in an abitrary direction in the complex plane. Question 2 (dumb I know but just out of curiosity): “Im CM = rho, other way around“ How this changes the logical statment? If CM=-i rho then i Cm= rho. Maybe I am thinking the wrong way. |
Q1: the mathematical sqrt sign is well defined using Arg function in the range -pi, pi. I'm not aware of any programming language, implementation that would mean anything different for sqrt. See the principal sqrt in
Q2: neither is true: CM != irho, However, Im CM = rho, and importantly only above the threshold. The functions differ by their real parts everywhere except a few points, and by their imaginary part below the threshold. |
slide 1: so cool figure :-)
slide 4: this is all first sheet, no second shown here.
The expression for rho does not have discontinuity on right.
slide 5: little * next to green stars are not explained
slide 6: Im CM = rho, other way around.
Violation of analyticity: mention pseudothreshold, and s=0
idea -> solution.
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